Exercise:
What is the value of \[ \LARGE \log_{\log_{\log_{\log_{\ldots} 27 } 27 } 27 } 27 =??\]
Solution:
Let $\log_{\log_{\log_{\log_{\ldots} 27 } 27 } 27 } 27=l $ then $\log_{l}27=l$
So by using the definition of logarithm $\log_{a}b=x$ iff $b={a}^{x}$ to get
${l}^{l}=27={3}^{3}$ hence $l=3$
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